Integrand size = 29, antiderivative size = 176 \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\frac {g^2 \sqrt {a+b x+c x^2}}{c e}+\frac {g (4 c e f-2 c d g-b e g) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{2 c^{3/2} e^2}+\frac {(e f-d g)^2 \text {arctanh}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{e^2 \sqrt {c d^2-b d e+a e^2}} \]
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Time = 0.18 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {1667, 857, 635, 212, 738} \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\frac {g \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right ) (-b e g-2 c d g+4 c e f)}{2 c^{3/2} e^2}+\frac {(e f-d g)^2 \text {arctanh}\left (\frac {-2 a e+x (2 c d-b e)+b d}{2 \sqrt {a+b x+c x^2} \sqrt {a e^2-b d e+c d^2}}\right )}{e^2 \sqrt {a e^2-b d e+c d^2}}+\frac {g^2 \sqrt {a+b x+c x^2}}{c e} \]
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Rule 212
Rule 635
Rule 738
Rule 857
Rule 1667
Rubi steps \begin{align*} \text {integral}& = \frac {g^2 \sqrt {a+b x+c x^2}}{c e}+\frac {\int \frac {\frac {1}{2} e \left (2 c e f^2-b d g^2\right )+\frac {1}{2} e g (4 c e f-2 c d g-b e g) x}{(d+e x) \sqrt {a+b x+c x^2}} \, dx}{c e^2} \\ & = \frac {g^2 \sqrt {a+b x+c x^2}}{c e}+\frac {(e f-d g)^2 \int \frac {1}{(d+e x) \sqrt {a+b x+c x^2}} \, dx}{e^2}+\frac {(g (4 c e f-2 c d g-b e g)) \int \frac {1}{\sqrt {a+b x+c x^2}} \, dx}{2 c e^2} \\ & = \frac {g^2 \sqrt {a+b x+c x^2}}{c e}-\frac {\left (2 (e f-d g)^2\right ) \text {Subst}\left (\int \frac {1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac {-b d+2 a e-(2 c d-b e) x}{\sqrt {a+b x+c x^2}}\right )}{e^2}+\frac {(g (4 c e f-2 c d g-b e g)) \text {Subst}\left (\int \frac {1}{4 c-x^2} \, dx,x,\frac {b+2 c x}{\sqrt {a+b x+c x^2}}\right )}{c e^2} \\ & = \frac {g^2 \sqrt {a+b x+c x^2}}{c e}+\frac {g (4 c e f-2 c d g-b e g) \tanh ^{-1}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{2 c^{3/2} e^2}+\frac {(e f-d g)^2 \tanh ^{-1}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{e^2 \sqrt {c d^2-b d e+a e^2}} \\ \end{align*}
Time = 0.70 (sec) , antiderivative size = 184, normalized size of antiderivative = 1.05 \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\frac {\frac {2 e g^2 \sqrt {a+x (b+c x)}}{c}+\frac {4 \sqrt {-c d^2+b d e-a e^2} (e f-d g)^2 \arctan \left (\frac {\sqrt {c} (d+e x)-e \sqrt {a+x (b+c x)}}{\sqrt {-c d^2+e (b d-a e)}}\right )}{c d^2+e (-b d+a e)}-\frac {g (-4 c e f+2 c d g+b e g) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+x (b+c x)}}\right )}{c^{3/2}}}{2 e^2} \]
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Time = 0.80 (sec) , antiderivative size = 259, normalized size of antiderivative = 1.47
method | result | size |
risch | \(\frac {g^{2} \sqrt {c \,x^{2}+b x +a}}{c e}-\frac {\frac {g \left (b e g +2 c d g -4 c e f \right ) \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x +a}\right )}{e \sqrt {c}}+\frac {2 \left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right ) c \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {\left (x +\frac {d}{e}\right )^{2} c +\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{e^{2} \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}}{2 e c}\) | \(259\) |
default | \(-\frac {g \left (\frac {d g \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x +a}\right )}{\sqrt {c}}-\frac {2 e f \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x +a}\right )}{\sqrt {c}}-e g \left (\frac {\sqrt {c \,x^{2}+b x +a}}{c}-\frac {b \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x +a}\right )}{2 c^{\frac {3}{2}}}\right )\right )}{e^{2}}-\frac {\left (d^{2} g^{2}-2 d e f g +e^{2} f^{2}\right ) \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {\left (x +\frac {d}{e}\right )^{2} c +\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{e^{3} \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}\) | \(301\) |
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Timed out. \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\text {Timed out} \]
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\[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\int \frac {\left (f + g x\right )^{2}}{\left (d + e x\right ) \sqrt {a + b x + c x^{2}}}\, dx \]
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Exception generated. \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\text {Exception raised: ValueError} \]
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Exception generated. \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {(f+g x)^2}{(d+e x) \sqrt {a+b x+c x^2}} \, dx=\int \frac {{\left (f+g\,x\right )}^2}{\left (d+e\,x\right )\,\sqrt {c\,x^2+b\,x+a}} \,d x \]
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